(D^2+1)Y=tanx

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Solution for (D^2+1)Y=tanx equation:


Simplifying
(D2 + 1) * Y = tanx

Reorder the terms:
(1 + D2) * Y = tanx

Reorder the terms for easier multiplication:
Y(1 + D2) = tanx
(1 * Y + D2 * Y) = tanx

Reorder the terms:
(D2Y + 1Y) = tanx
(D2Y + 1Y) = tanx

Solving
D2Y + 1Y = antx

Solving for variable 'D'.

Move all terms containing D to the left, all other terms to the right.

Add '-1Y' to each side of the equation.
D2Y + 1Y + -1Y = -1Y + antx

Combine like terms: 1Y + -1Y = 0
D2Y + 0 = -1Y + antx
D2Y = -1Y + antx

Divide each side by 'Y'.
D2 = -1 + antxY-1

Simplifying
D2 = -1 + antxY-1

Reorder the terms:
1 + D2 + -1antxY-1 = -1 + antxY-1 + 1 + -1antxY-1

Reorder the terms:
1 + D2 + -1antxY-1 = -1 + 1 + antxY-1 + -1antxY-1

Combine like terms: -1 + 1 = 0
1 + D2 + -1antxY-1 = 0 + antxY-1 + -1antxY-1
1 + D2 + -1antxY-1 = antxY-1 + -1antxY-1

Combine like terms: antxY-1 + -1antxY-1 = 0
1 + D2 + -1antxY-1 = 0

The solution to this equation could not be determined.

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